(1) | THE HOLDER | } | on which are mounted spiral logarithmic scales. |
(2) | THE CYLINDER | ||
(3) | THE CURSOR (or Indicator), carrying at each end an engraved arrow, or pointer, which can be set to any mark, or to which any mark can be set. |
By | ·001 | from | 1 | to | 1·12 | By | ·005 | from | 2 | to | 4. | |
,, | ·002 | ,, | 1·12 | ,, | 2 | ,, | ·01 | ,, | 4 | ,, | 10. |
MOVEMENT 1. | Take the HOLDER in the left hand, and open Instrument gently to full extent. Move CURSOR to set bottom arrow. |
MOVEMENT 2. | Move CYLINDER so that number on scale is set to top arrow (not the arrow to the number). Do not touch Cursor while moving Cylinder. |
MOVEMENT 3. | Move CURSOR to set either arrow as required — the companion arrow will then point to the answer (see following examples). |
B = | Bottom Arrow or Pointer on Cursor. | ||
T = | Top arrow or Pointer on Cursor. | ||
Unity = | { | Middle Unity on Model K. Available Unity on Model L (see previous page). |
To MULTIPLY. | To DIVIDE. | |
1. Set B to Multiplicand. | 1. Set B to Dividend. | |
2. Set UNITY to T. | 2. Set Divisor to T. | |
3. Move T to Multiplier. | 3. Move T to UNITY. | |
4. Read Answer at B. |
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Set B to 6. Set 7 to T. Move T to 4. | |||
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Set 5 to T. Move T to 9. | |||
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Set 2 to T. Move T to UNITY. Read answer at B: 3·086. |
I. | Solve 12:7::16:x ? Set B to 12. Set 7 to T. Move B to 16. Read answer at T. 12:7::16:9·333. |
II. | Solve 18:4::x:53 ? Set B to 18. Set 4 to T. Move T to 53. Read answer at B. 18:4::238·5:53. |
III. | Divide 8975 in the proportions
83:79:33:19. Set B to 8975. Set sum of required proportions, viz., 214, to T. Without altering the setting of the Instrument, move T in succession to 83, 79, 33, 19, and read the corresponding proportions at B, viz., 3481, 3313, 1384 and 797. (On Model L this calculation necessitates "closing in" the Cylinder. See page 6.) |
II. | Decimalise 3/32, 7/32, 15/32,
29/32. Set B to 32. Set UNITY to T (32 and 1 being the constants in this series). Move B in succession to 3, 7, 15, 29 and read corresponding answers at T, viz., ·09375, ·21875, ·46875, ·9062. |
To CLOSE CYLINDER IN. | Move T to bottom UNITY. Set top UNITY to T. |
To OPEN CYLINDER OUT. | Move T to top UNITY. Set bottom UNITY to T. |
1·0083·1
x 3√63
x 4000 6 x 5√260000 x 421·82 | = ·2495 |
1·025
x 3·98
x 4000 6 x 12·11 x 900·1 |
POWERS. | ROOTS. | |
Multiply the logarithm of the number by the index of the power and take the antilogarithm of the product. | Divide the logarithm of the number by the index of the root and take the antilogarithm of the quotient. | |
Example :— What is
1·0083·1 Log. of 1·008=0·0035. 0·0035x3·1=0·01085. Antilog. of 0·01085=1·025. Therefore 1·0083·1=1·025. |
Example :— What is
3√63. Log. of 63=1·7993. 1·7993/3=0·5998. Antilog. of 0·5998=3·98. Therefore 3√63=3·98. |
have | 5430000, +7 |
674, +3, |
81·2, +2, |
7·82, +1, |
0·45, +0, |
0·0421, –1, |
0·00675; –2 |
places |
To find the number of places (p) in the product (P=XxY). | ||
Let X have m places, and Y have n places. | ||
RULE I. | p=m+n or p=m+n–1. | |
(a) When the result is below the original setting p=m+n. | ||
Example: 3x4 (m=1; n=1). Set B to 3. Set UNITY to T. Move T to 4 (This is below setting.) p=m+n=2. Answer=12. |
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(b) When the result is above the setting, the product has m+n–1 places | ||
Example: 3x3 (m=1; n=1). Set B to 3. Set UNITY to T. Move T to 3. (This is above setting.) p=m+n–1=1. Answer=9. |
To find the number of places (q) in the quotient (Q=X/Y). | ||
RULE II. | q=m–n or q=m–n+1 as follows :— | |
(c) When the result is above the setting, the quotient has m–n places. | ||
Example: 3÷4 (m=1; n=1). Set B to 3. Set 4 to T. Move T to UNITY. (This is above setting.) q=m–n=0. Answer=0·75. |
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(d) When the result is below the setting, the quotient has m–n+1 places. | ||
Example: 5÷4 (m=1; n=1). Set B to 5. Set 4 to T. Move T to UNITY. Read answer at B. (This is below setting.) q=1–1+1=+1. Answer=1·25. |
RULE III. | Two methods may be used in working out complex problems involving both multiplication and division. They are :— | |
(1) | Taking numerator and denominator alternately. | |
(2) | Taking all the numerators first and then dividing consecutively by the denominators. |
Example: | 432 x 32·4
x 0·0217 x 0·98 0·00000621 x 412000 x 0·175 x 4·71 |
=141·14... | |||||||
No. | of | places | in | factors | of | numerator | =3+2+(–1)+0 | = +4. | |
,, | ,, | ,, | ,, | ,, | ,, | denominator | = –5+6+0+1 | = +2.
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Difference | = +2. | ||||||||
Results of various steps in calculation | = –1+1+1 | = +1. |
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Number of places in answer | = +3. | ||||||||
Answer = 141·14. |
Andries de Man 5/15/1997